post请求 url后面加参数 接收不到的,必须 放到send("use"=user)形式
还要加上
xhr.setRequestHeader("Content-Type","application/x-www-form-urlencoded");
servlet
1 package cn.itcast.controller; 2 3 import java.io.IOException; 4 import javax.servlet.ServletException; 5 import javax.servlet.annotation.WebServlet; 6 import javax.servlet.http.HttpServlet; 7 import javax.servlet.http.HttpServletRequest; 8 import javax.servlet.http.HttpServletResponse; 9 10 @WebServlet("/servlet/ServletDemo2")11 public class ServletDemo2 extends HttpServlet {12 private static final long serialVersionUID = 1L;13 14 public void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {15 }16 17 public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {18 //System.out.println("ServletDemo2 doPost running");19 String username = request.getParameter("username");20 String password = request.getParameter("password");21 System.out.println(username+":"+password);22 }23 24 }
jsp
1 2 3 4 5AJAX进行post方式的请求测试 6 7 8 910 1112 51 52